Guest guest Posted February 26, 2012 Report Share Posted February 26, 2012 That's excellent sajitha.Thank you very much.I have been trying to find this one. Thanks & Regards,Padma From: Sajithakumari Sivaprem <ssajithakumari@...> " " < > Sent: Sunday, 26 February 2012, 20:40 Subject: FLUORIDE CALCULATION Hi Ebtisam, 1mg/ml=1000ppm=1g/1000ml 1g/100ml=1% solution =10000ppm so to convert 0.023% F=230PPM How we calculate fluoride in o.o5Na F The molecular wt of Na is23 and fluorine is19 so the total molecular wtis23+19=42 19/42=0.45 ie45% ,fluoride ions in 0.05%Na F 0.2%NaF =0.45X0.2=.090%F=900PPM SO WE WANT TO REMEMBER THESE VALUES FOR DIFFT PREPARATIONS NaF=45% SnF2=24% APF=100% MFP(SODIUM MONO FLOURO PHOSPHATE paste)=14%( GOOGLE) 1mg/gm of paste=1000ppmI think this will suffice for the exam purpose regards sajitha Quote Link to comment Share on other sites More sharing options...
Guest guest Posted February 26, 2012 Report Share Posted February 26, 2012 Thanx sajitha .that's brilliant. ------------------ Quote Link to comment Share on other sites More sharing options...
Guest guest Posted February 26, 2012 Report Share Posted February 26, 2012 Thanks for wonderful explanation. From: Sajithakumari Sivaprem <ssajithakumari@...> " " < > Sent: Sunday, 26 February 2012 8:40 PM Subject: FLUORIDE CALCULATION Hi Ebtisam, 1mg/ml=1000ppm=1g/1000ml 1g/100ml=1% solution =10000ppm so to convert 0.023% F=230PPM How we calculate fluoride in o.o5Na F The molecular wt of Na is23 and fluorine is19 so the total molecular wtis23+19=42 19/42=0.45 ie45% ,fluoride ions in 0.05%Na F 0.2%NaF =0.45X0.2=.090%F=900PPM SO WE WANT TO REMEMBER THESE VALUES FOR DIFFT PREPARATIONS NaF=45% SnF2=24% APF=100% MFP(SODIUM MONO FLOURO PHOSPHATE paste)=14%( GOOGLE) 1mg/gm of paste=1000ppmI think this will suffice for the exam purpose regards sajitha Quote Link to comment Share on other sites More sharing options...
Guest guest Posted February 26, 2012 Report Share Posted February 26, 2012 Hello everybody,I'm divya answering ore1 in april.I'm practicing in mumbai India for the last 17 yrs.Anybody out there like me who is studying dentistry after such a long gap? Do we have to go through all the books recommended by the ore site ? From: Kanika Kohli <kanika_sahil@...> " " < > Sent: Monday, 27 February 2012 5:35 AM Subject: Re: FLUORIDE CALCULATION Thanks for wonderful explanation. From: Sajithakumari Sivaprem <ssajithakumari@...> " " < > Sent: Sunday, 26 February 2012 8:40 PM Subject: FLUORIDE CALCULATION Hi Ebtisam, 1mg/ml=1000ppm=1g/1000ml 1g/100ml=1% solution =10000ppm so to convert 0.023% F=230PPM How we calculate fluoride in o.o5Na F The molecular wt of Na is23 and fluorine is19 so the total molecular wtis23+19=42 19/42=0.45 ie45% ,fluoride ions in 0.05%Na F 0.2%NaF =0.45X0.2=.090%F=900PPM SO WE WANT TO REMEMBER THESE VALUES FOR DIFFT PREPARATIONS NaF=45% SnF2=24% APF=100% MFP(SODIUM MONO FLOURO PHOSPHATE paste)=14%( GOOGLE) 1mg/gm of paste=1000ppmI think this will suffice for the exam purpose regards sajitha Quote Link to comment Share on other sites More sharing options...
Guest guest Posted February 27, 2012 Report Share Posted February 27, 2012 cheers padma,munazza and kanika.... From: Padma Priya <padmaraj_78@...> " " < > Sent: Sunday, 26 February 2012 9:22 PM Subject: Re: FLUORIDE CALCULATION That's excellent sajitha.Thank you very much.I have been trying to find this one. Thanks & Regards,Padma From: Sajithakumari Sivaprem <ssajithakumari@...> " " < > Sent: Sunday, 26 February 2012, 20:40 Subject: FLUORIDE CALCULATION Hi Ebtisam, 1mg/ml=1000ppm=1g/1000ml 1g/100ml=1% solution =10000ppm so to convert 0.023% F=230PPM How we calculate fluoride in o.o5Na F The molecular wt of Na is23 and fluorine is19 so the total molecular wtis23+19=42 19/42=0.45 ie45% ,fluoride ions in 0.05%Na F 0.2%NaF =0.45X0.2=.090%F=900PPM SO WE WANT TO REMEMBER THESE VALUES FOR DIFFT PREPARATIONS NaF=45% SnF2=24% APF=100% MFP(SODIUM MONO FLOURO PHOSPHATE paste)=14%( GOOGLE) 1mg/gm of paste=1000ppmI think this will suffice for the exam purpose regards sajitha Quote Link to comment Share on other sites More sharing options...
Guest guest Posted February 29, 2012 Report Share Posted February 29, 2012 Thanks Sajitha , it's very helpfullSent from my iPhoneOn 26 Feb 2012, at 20:40, Sajithakumari Sivaprem <ssajithakumari@...> wrote: Hi Ebtisam, 1mg/ml=1000ppm=1g/1000ml 1g/100ml=1% solution =10000ppm so to convert 0.023% F=230PPM How we calculate fluoride in o.o5Na F The molecular wt of Na is23 and fluorine is19 so the total molecular wtis23+19=42 19/42=0.45 ie45% ,fluoride ions in 0.05%Na F 0.2%NaF =0.45X0.2=.090%F=900PPM SO WE WANT TO REMEMBER THESE VALUES FOR DIFFT PREPARATIONS NaF=45% SnF2=24% APF=100% MFP(SODIUM MONO FLOURO PHOSPHATE paste)=14%( GOOGLE) 1mg/gm of paste=1000ppmII think this will suffice for the exam purpose regards sajitha = Quote Link to comment Share on other sites More sharing options...
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