Guest guest Posted February 26, 2012 Report Share Posted February 26, 2012 Hi Ebtisam, 1mg/ml=1000ppm=1g/1000ml 1g/100ml=1% solution =10000ppm so to convert 0.023% F=230PPM How we calculate fluoride in o.o5Na F The molecular wt of Na is23 and fluorine is19 so the total molecular wtis23+19=42 19/42=0.45 ie45% ,fluoride ions in 0.05%Na F 0.2%NaF =0.45X0.2=.090%F=900PPM SO WE WANT TO REMEMBER THESE VALUES FOR DIFFT PREPARATIONS NaF=45% SnF2=24% APF=100% MFP(SODIUM MONO FLOURO PHOSPHATE paste)=14%( GOOGLE) 1mg/gm of paste=1000ppmI think this will suffice for the exam purpose regards sajitha Quote Link to comment Share on other sites More sharing options...
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