Guest guest Posted July 31, 2007 Report Share Posted July 31, 2007 From my previous message, > " body density (mass density/volume) " Sorry but after rereading this, it occurred to me that this could be slighlty confusing to some. What I meant was, " body density (mass/volume) " a=z Quote Link to comment Share on other sites More sharing options...
Guest guest Posted August 1, 2007 Report Share Posted August 1, 2007 Yargg - almost wish I hadn't done this experiment. Anyway (a=z) ~ 77.9 Liters to 80.194 Liters of stuff I won't mention what the Brozek and Siri formulas predict for my %BF, but based upon my past readings when I was 10/15 lbs lighter, am guessing the values are very close to reality. Also as an aside there is about 4.7 more gallons of me than when I ran the 100 in 10.2 sec at age 17. No wonder I'm not so spry anymore. Anyway this finding is a real kick in the pants and I am like totally skipping dinner tonight. (I may get drunk on red wine instead) So this bear a=z is going back into hibernation for now - maybe I'll be lighter tomorrow. a=z > > > > From my previous message, > > > > > " body density (mass density/volume) " > > > > Sorry but after rereading this, it occurred to me that this could be > > slighlty confusing to some. What I meant was, > > > > " body density (mass/volume) " > > > > a=z > > > Quote Link to comment Share on other sites More sharing options...
Guest guest Posted August 1, 2007 Report Share Posted August 1, 2007 Rodney, I think that your calculations are about twice what they should be. E.g., at 12.2%BF the density is 1.07140 kg/liter. A 150 lb person weighs 68 kg (150/2.2). Dividing the weight by the density gives a volume of 68/1.0714 = 63 liters. This means that you need 5 liters (68 - 63) for flotation since the density of water is 1 kg/liter. This is slightly bigger than a one-gallon jug. Tony > > > > From my previous message, > > > > > " body density (mass density/volume) " > > > > Sorry but after rereading this, it occurred to me that this could be > > slighlty confusing to some. What I meant was, > > > > " body density (mass/volume) " > > > > a=z > > > Quote Link to comment Share on other sites More sharing options...
Guest guest Posted August 1, 2007 Report Share Posted August 1, 2007 Hi Tony: Thank you. You are right! I mixed up metric with imperial measurements. DUH! Please cancel that thought about the danger of drowning : ^ ))) I hope the following table is a lot more accurate: The following applies for the number of liters of flotation required given BF% for someone weighing 150 pounds (68.04 kg): BF% Density Liters ------- ---------- --------- 23.0 1.04610 ~3 15.9 1.06250 ~4 ~8.9 1.07930 ~5 ~2.0 1.09670 ~6 So the above table (if I got it right this time! and if you know very approximately what you BF% is) will tell you how much flotation you will need when you do the experiment at the pool. Perhaps Tony would be kind enough to make sure I have it right this time : ^ ))) Rodney. > > Rodney, > > I think that your calculations are about twice what they should be. > E.g., at 12.2%BF the density is 1.07140 kg/liter. > A 150 lb person weighs 68 kg (150/2.2). Dividing the weight by the > density gives a volume of 68/1.0714 = 63 liters. This means that you > need 5 liters (68 - 63) for flotation since the density of water is 1 > kg/liter. This is slightly bigger than a one-gallon jug. > > Tony > > > --- In , " Rodney " <perspect1111@> wrote: > > > > Hi Aequalsz: > > > > GOOD stuff. Thank you! > > > > It seems to me from that article that the following applies for the > > number of liters of flotation required according to BF% for someone > > weighing 150 pounds: > > > > BF% Density Liters > > ---- ------- ------ > > 18.5 1.05630 ~8 > > 15.4 1.06380 ~9 > > 12.2 1.07140 ~10 > > 9.0 1.07910 ~11 > > 5.5 1.08700 ~12 > > 2.6 1.09490 ~13 > > > > That is a lot more flotation than I would have expected would be > > required to keep someone afloat! > > > > Has anyone ever considered an increased drowning risk for people on > > CRON? ;; ^ ))) > > > > Rodney. > > > > PS: I hope I got my calculations right! > > > > --- In , " aequalsz " <aequalsz@> wrote: > > > > > > From my previous message, > > > > > > > " body density (mass density/volume) " > > > > > > Sorry but after rereading this, it occurred to me that this could be > > > slighlty confusing to some. What I meant was, > > > > > > " body density (mass/volume) " > > > > > > a=z Quote Link to comment Share on other sites More sharing options...
Guest guest Posted August 1, 2007 Report Share Posted August 1, 2007 Hi Tony: I now see that while we are a lot closer than we were previously, we are still not exactly in agreement. So this is what I did: I took the case where someone weighing 68.04 kg needs five liters of flotation, and concluded that: his density is 68.04÷(68.04-5) = 1.0793 According to the equations that translates to a BF% (averaged) of 8.9% ------------- Taking the case of a 68.04kg person needing four litres of flotation: his density is 68.04÷(68.04-4) = 1.0625 Which gives an average BF% of 15.9% ------------- Does this make sense to you? Or am I out to lunch ........ again? Rodney. > > > > > > > > From my previous message, > > > > > > > > > " body density (mass density/volume) " > > > > > > > > Sorry but after rereading this, it occurred to me that this > could be > > > > slighlty confusing to some. What I meant was, > > > > > > > > " body density (mass/volume) " > > > > > > > > a=z > Quote Link to comment Share on other sites More sharing options...
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