I think I figured out how RIFM came up with .02%.

[Guest guest]

(First, I have removed all contractions and I hope that this will have

removed all gibberish that is common with my posts.)

As the subject line says, I think I figured out how RIFM came up with

..02% max methyleugenol concentration within a perfume.

Before I go into the how, though, I want to use the percent to

calculate the allowable amount of 3.5%-methyleugenol rose oil.

If methyleugenol is allowed at .02% in the finished good (20%

perfume), and a rose oil containing 3.5% methyleugenol is used, then

only .57142% of that rose oil would be allowed in the finished good.

The calculation is ((.02/3.5)*100).

*** Now here is the how. ***

First major consideration:

RIFM is assuming a daily application (of CATEGORY 4 products which

include lotions) of .3 gram.

Alternatively, I am assuming a daily application of .17 g of perfume.

I think we can alter the application size to make our concentration

aromatically desirable. So, taking this assumed application size of

..17 g into account, we might be able to up the percentage--of rose

oil, in this example--to 1.008388%.)

The calculation, I think, should be: ((.3/.17) x .57142).

Next, note that I did with the the NOELS what RIFM did.

Divided them by 10 and then 1000.

*** (They also increased the result of this division to account for an

only 40% dermal penetration, but I am going to scratch that for

simplicity. And, actually, since my numbers--you will see at the

end--came out to about the above 1.008388% of a daily application, I

truthfully still do not understand what RIFM did to their numbers to

arrive at .02%.) ***

Moving right along...

The lowest NOEL for methyleugenol I found was 10 mg/kg of bodyweight

per day.

An avg. person weighs 60 kg. So, we take 10 mg and multiply it by 60.

For starters.

That is 600 mg methyleugenol/avg. (small) person/day.

600 mg not shown to have any noticeable affect on a (rat or mouse).

Next...

Divide that by 10 and then 1000...so, by 10,000.

600 mg / 10,000

equals .06 mg methyleugenol per day (max).

Now, a small drop of alcohol equals about .016 g or 16 mg.

If rose oil weighs more...say, .017 g or 17 mg per small drop...

Applying 10 small drops (per day) of straight rose oil means we'd be

putting on 17 mg x 10...170 mg of rose oil each day.

But in a perfume of 20% aromatic concentration, if we were using rose

oil as the only aromatic in the perfume, 170 mg x .2 =

34 mg of rose oil applied per day (in the 10 small drops of perfume).

Still with me? Goody.

Now, as stated at the beginning, the rose oil we want to use contains

3.5% methyleugenol...

***** Here is another part I do not understand....

Is 3.5% a VOLUME measurement? Or WEIGHT? Or would either work? ****

I will use weight until I know which it is.

So now I want to know how much methyleugenol, in *milligrams*, there

is in the 34 mg of rose oil.

34 mg x .035 (3.5%) = 1.19 mg. of methyleugenol *applied* (in our

theoretical example)

.....Going back to the max of .06 mg of methyleugenol *suggested* per

day...

..06 mg max ME divided by 1.19 mg applied ME = .0504

converting that to a percent... 5.04%

*** Our really safe max would equal 5.04% of what we applied?? ***

If so, our max would be 5.04% of 10 small drops of a 20% rose perfume.

We could look at that two ways:

A) 5.04% of 10 small drops = .504 drop.

That's a maximum of .504 drop of a 20% rose perfume per day, yes?

5.04% of 20% = 1.008%

That's 10 small drops of 1.008% rose perfume, also yes?

The median, then, would be 5 small drops of 10.504% rose oil perfume

per day. Doable aroma concentration.

~Jen