Guest guest Posted August 24, 2007 Report Share Posted August 24, 2007 I have found a cheap source of Mag Citrate and Zn Citrate in NSW Australia (email privately for details) but need to figure out how much I am getting per gram as I am buying per kg. High school chem is locked away deep in forgotten memory and I am unable to work it out, can anyone here guide me through so I can work it out in the future if need be? A google search tells me the formulas(?) are Mg Citrate C12H6Mg07.5H20 Zn Citrate Zn3(C6H5)7)22.H20 Are these correct? How much Mg/Zn per gram does that work out to be? Thanks in advance, Kelle Quote Link to comment Share on other sites More sharing options...
Guest guest Posted August 26, 2007 Report Share Posted August 26, 2007 My Merck index says that magnesium citrate is C12H10Mg3O14, and is 16% Mg. (The formula you have found is for magnesium citrate dibasic). For zinc citrate, C12H10O14Zn3, 34 % Zn. > > I have found a cheap source of Mag Citrate and Zn Citrate in NSW > Australia (email privately for details) but need to figure out how > much I am getting per gram as I am buying per kg. > High school chem is locked away deep in forgotten memory and I am > unable to work it out, can anyone here guide me through so I can work > it out in the future if need be? > > A google search tells me the formulas(?) are > > Mg Citrate > C12H6Mg07.5H20 > > Zn Citrate > Zn3(C6H5)7)22.H20 > > Are these correct? > > How much Mg/Zn per gram does that work out to be? > > Thanks in advance, > Kelle > Quote Link to comment Share on other sites More sharing options...
Guest guest Posted August 27, 2007 Report Share Posted August 27, 2007 Thanks , I was told it was " easy " to work out how much in there if knew the molecular weight of the formula. Do you know how to work it out? I keep coming up with 7.6% for both of them: 3(Zn or Mg mols)/39 (the total nr of mols)x100 This is way off yrs, how did you work it out? Or is that what the Merck says? Thanks, Kelle > > My Merck index says that magnesium citrate is C12H10Mg3O14, and is 16% > Mg. (The formula you have found is for magnesium citrate dibasic). > > For zinc citrate, C12H10O14Zn3, 34 % Zn. > > > > > Quote Link to comment Share on other sites More sharing options...
Guest guest Posted August 27, 2007 Report Share Posted August 27, 2007 I got the percentages directly from the Merck index. This is how to calculate. Mg citrate = 451 g/mole, Mg = 24 g/mole Mg citrate has 3 x Mg 3*24/451 * 100 = 16% Zn citrate = 574 g/mole, Zn = 65 g/mole Zn citrate has 3 x Zn 3*65/574 * 100 = 34% > > Thanks , > I was told it was " easy " to work out how much in there if knew the > molecular weight of the formula. Do you know how to work it out? I > keep coming up with 7.6% for both of them: 3(Zn or Mg mols)/39 (the > total nr of mols)x100 > This is way off yrs, how did you work it out? Or is that what the > Merck says? > > Thanks, > Kelle > > > > > My Merck index says that magnesium citrate is C12H10Mg3O14, and is 16% > > Mg. (The formula you have found is for magnesium citrate dibasic). > > > > For zinc citrate, C12H10O14Zn3, 34 % Zn. > > > > > > > > > > > Quote Link to comment Share on other sites More sharing options...
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